36x^(4)+3x^2+1/16

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Solution for 36x^(4)+3x^2+1/16 equation: 


x in (-oo:+oo)

36*x^4+3*x^2+1/16 = 0

t_1 = x^2

36*t_1^2+3*t_1^1+1/16 = 0

36*t_1^2+3*t_1+1/16 = 0

DELTA = 3^2-(1/16*4*36)

DELTA = 0

t_1 = -3/(2*36)

t_1 = -1/24 or t_1 = -1/24

t_1 = -1/24

x^2+1/24 = 0

1*x^2 = -1/24 // : 1

x^2 = -1/24

t_1 = -1/24

x^2+1/24 = 0

1*x^2 = -1/24 // : 1

x^2 = -1/24

x belongs to the empty set

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